# (2x-7)(6x+7)=0

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## Solution for (2x-7)(6x+7)=0 equation:

(2x-7)(6x+7)=0
We multiply parentheses ..
(+12x^2+14x-42x-49)=0
We get rid of parentheses
12x^2+14x-42x-49=0
We add all the numbers together, and all the variables
12x^2-28x-49=0
a = 12; b = -28; c = -49;Δ = b2-4acΔ = -282-4·12·(-49)Δ = 3136The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-56}{2*12}=\frac{-28}{24} =-1+1/6$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+56}{2*12}=\frac{84}{24} =3+1/2$

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