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(2x-7)(3x+5)=153
We move all terms to the left:
(2x-7)(3x+5)-(153)=0
We multiply parentheses ..
(+6x^2+10x-21x-35)-153=0
We get rid of parentheses
6x^2+10x-21x-35-153=0
We add all the numbers together, and all the variables
6x^2-11x-188=0
a = 6; b = -11; c = -188;
Δ = b2-4ac
Δ = -112-4·6·(-188)
Δ = 4633
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{4633}}{2*6}=\frac{11-\sqrt{4633}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{4633}}{2*6}=\frac{11+\sqrt{4633}}{12} $
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