(2x-7)(3x+1)=(2x-5)(3x-1)

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Solution for (2x-7)(3x+1)=(2x-5)(3x-1) equation: 



(2x-7)(3x+1)=(2x-5)(3x-1)

We move all terms to the left:

(2x-7)(3x+1)-((2x-5)(3x-1))=0

We multiply parentheses ..

(+6x^2+2x-21x-7)-((2x-5)(3x-1))=0



We calculate terms in parentheses: -((2x-5)(3x-1)), so:

(2x-5)(3x-1)

We multiply parentheses ..

(+6x^2-2x-15x+5)

We get rid of parentheses

6x^2-2x-15x+5

We add all the numbers together, and all the variables

6x^2-17x+5

Back to the equation:

-(6x^2-17x+5)



We get rid of parentheses

6x^2-6x^2+2x-21x+17x-7-5=0

We add all the numbers together, and all the variables

-2x-12=0

We move all terms containing x to the left, all other terms to the right

-2x=12

x=12/-2

x=-6

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