(2x-6)/3=(x+1)/2

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Solution for (2x-6)/3=(x+1)/2 equation: 



(2x-6)/3=(x+1)/2

We move all terms to the left:

(2x-6)/3-((x+1)/2)=0

We calculate fractions


2x/()+(-((x+1)*3)/()=0



We calculate terms in parentheses: +(-((x+1)*3)/(), so:

-((x+1)*3)/(

We multiply all the terms by the denominator


-((x+1)*3)



We calculate terms in parentheses: -((x+1)*3), so:

(x+1)*3

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

-3x-3

Back to the equation:

+(-3x-3)



We get rid of parentheses

2x/()-3x-3=0

We multiply all the terms by the denominator


2x-3x*()-3*()=0

We add all the numbers together, and all the variables

2x-3x*()=0

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