(2x-6)/2=(8x+11)/3

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Solution for (2x-6)/2=(8x+11)/3 equation: 



(2x-6)/2=(8x+11)/3

We move all terms to the left:

(2x-6)/2-((8x+11)/3)=0

We calculate fractions


2x/()+(-((8x+11)*2)/()=0



We calculate terms in parentheses: +(-((8x+11)*2)/(), so:

-((8x+11)*2)/(

We multiply all the terms by the denominator


-((8x+11)*2)



We calculate terms in parentheses: -((8x+11)*2), so:

(8x+11)*2

We multiply parentheses

16x+22

Back to the equation:

-(16x+22)



We get rid of parentheses

-16x-22

Back to the equation:

+(-16x-22)



We get rid of parentheses

2x/()-16x-22=0

We multiply all the terms by the denominator


2x-16x*()-22*()=0

We add all the numbers together, and all the variables

2x-16x*()=0

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