(2x-6)-(3x-4)=(-4+x)-4X+6

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Solution for (2x-6)-(3x-4)=(-4+x)-4X+6 equation: 



(2x-6)-(3x-4)=(-4+x)-4x+6

We move all terms to the left:

(2x-6)-(3x-4)-((-4+x)-4x+6)=0

We add all the numbers together, and all the variables

(2x-6)-(3x-4)-((x-4)-4x+6)=0

We get rid of parentheses

2x-3x-((x-4)-4x+6)-6+4=0



We calculate terms in parentheses: -((x-4)-4x+6), so:

(x-4)-4x+6

We add all the numbers together, and all the variables

-4x+(x-4)+6

We get rid of parentheses

-4x+x-4+6

We add all the numbers together, and all the variables

-3x+2

Back to the equation:

-(-3x+2)



We add all the numbers together, and all the variables

-1x-(-3x+2)-2=0

We get rid of parentheses

-1x+3x-2-2=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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