(2x-5y)(2x+5y)=

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Solution for (2x-5y)(2x+5y)= equation:


Simplifying
(2x + -5y)(2x + 5y) = 0

Multiply (2x + -5y) * (2x + 5y)
(2x * (2x + 5y) + -5y * (2x + 5y)) = 0
((2x * 2x + 5y * 2x) + -5y * (2x + 5y)) = 0

Reorder the terms:
((10xy + 4x2) + -5y * (2x + 5y)) = 0
((10xy + 4x2) + -5y * (2x + 5y)) = 0
(10xy + 4x2 + (2x * -5y + 5y * -5y)) = 0
(10xy + 4x2 + (-10xy + -25y2)) = 0

Reorder the terms:
(10xy + -10xy + 4x2 + -25y2) = 0

Combine like terms: 10xy + -10xy = 0
(0 + 4x2 + -25y2) = 0
(4x2 + -25y2) = 0

Solving
4x2 + -25y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '25y2' to each side of the equation.
4x2 + -25y2 + 25y2 = 0 + 25y2

Combine like terms: -25y2 + 25y2 = 0
4x2 + 0 = 0 + 25y2
4x2 = 0 + 25y2
Remove the zero:
4x2 = 25y2

Divide each side by '4'.
x2 = 6.25y2

Simplifying
x2 = 6.25y2

Take the square root of each side:
x = {-2.5y, 2.5y}

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