(2x-5)/9=(3x-7)/7

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Solution for (2x-5)/9=(3x-7)/7 equation: 



(2x-5)/9=(3x-7)/7

We move all terms to the left:

(2x-5)/9-((3x-7)/7)=0

We calculate fractions


2x/()+(-((3x-7)*9)/()=0



We calculate terms in parentheses: +(-((3x-7)*9)/(), so:

-((3x-7)*9)/(

We multiply all the terms by the denominator


-((3x-7)*9)



We calculate terms in parentheses: -((3x-7)*9), so:

(3x-7)*9

We multiply parentheses

27x-63

Back to the equation:

-(27x-63)



We get rid of parentheses

-27x+63

Back to the equation:

+(-27x+63)



We get rid of parentheses

2x/()-27x+63=0

We multiply all the terms by the denominator


2x-27x*()+63*()=0

We add all the numbers together, and all the variables

2x-27x*()=0

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