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(2x-5)/4x+1=6
We move all terms to the left:
(2x-5)/4x+1-(6)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
(2x-5)/4x-5=0
We multiply all the terms by the denominator
(2x-5)-5*4x=0
Wy multiply elements
(2x-5)-20x=0
We get rid of parentheses
2x-20x-5=0
We add all the numbers together, and all the variables
-18x-5=0
We move all terms containing x to the left, all other terms to the right
-18x=5
x=5/-18
x=-5/18
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