(2x-5)/31/5

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Solution for (2x-5)/31/5 equation: 


x in (-oo:+oo)

(2*x-5)/3 < 1/5 // - 1/5

(2*x-5)/3-(1/5) < 0

(2*x-5)/3-1/5 < 0

(5*(2*x-5))/(3*5)+(-1*3)/(3*5) < 0

5*(2*x-5)-1*3 < 0

10*x-28 < 0

(10*x-28)/(3*5) < 0

(10*x-28)/(3*5) < 0 // * (3*5)^2

3*5*(10*x-28) < 0

( 10*x-28 )

10*x-28 < 0 // + 28

10*x < 28 // : 10

x < 28/10

x < 14/5

( 3 )

3 < 0

x belongs to the empty set

( 5 )

5 < 0

x belongs to the empty set

	(-oo:14/5)	(14/5:+oo)
10*x-28	-	+
3	+	+
5	+	+


x in (-oo:14/5)

(-oo:14/5)

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