(2x-5)/2=(4x-9)/8

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Solution for (2x-5)/2=(4x-9)/8 equation: 



(2x-5)/2=(4x-9)/8

We move all terms to the left:

(2x-5)/2-((4x-9)/8)=0

We calculate fractions


2x/()+(-((4x-9)*2)/()=0



We calculate terms in parentheses: +(-((4x-9)*2)/(), so:

-((4x-9)*2)/(

We multiply all the terms by the denominator


-((4x-9)*2)



We calculate terms in parentheses: -((4x-9)*2), so:

(4x-9)*2

We multiply parentheses

8x-18

Back to the equation:

-(8x-18)



We get rid of parentheses

-8x+18

Back to the equation:

+(-8x+18)



We get rid of parentheses

2x/()-8x+18=0

We multiply all the terms by the denominator


2x-8x*()+18*()=0

We add all the numbers together, and all the variables

2x-8x*()=0

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