(2x-5)-(5x+1)=8+-(2+7x)

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Solution for (2x-5)-(5x+1)=8+-(2+7x) equation: 



(2x-5)-(5x+1)=8+-(2+7x)

We move all terms to the left:

(2x-5)-(5x+1)-(8+-(2+7x))=0

We add all the numbers together, and all the variables

(2x-5)-(5x+1)-(8+-(7x+2))=0

We use the square of the difference formula

(2x-5)-(5x+1)-(8-(7x+2))=0

We get rid of parentheses

2x-5x-(8-(7x+2))-5-1=0



We calculate terms in parentheses: -(8-(7x+2)), so:

8-(7x+2)

determiningTheFunctionDomain
-(7x+2)+8

We get rid of parentheses

-7x-2+8

We add all the numbers together, and all the variables

-7x+6

Back to the equation:

-(-7x+6)



We add all the numbers together, and all the variables

-3x-(-7x+6)-6=0

We get rid of parentheses

-3x+7x-6-6=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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