(2x-5)+28=127

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Solution for (2x-5)+28=127 equation: 



(2x-5)+28=127

We move all terms to the left:

(2x-5)+28-(127)=0

We add all the numbers together, and all the variables

(2x-5)-99=0

We get rid of parentheses

2x-5-99=0

We add all the numbers together, and all the variables

2x-104=0

We move all terms containing x to the left, all other terms to the right

2x=104

x=104/2

x=52

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