(2x-5)+(2x-5)+x+x=38

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Solution for (2x-5)+(2x-5)+x+x=38 equation: 



(2x-5)+(2x-5)+x+x=38

We move all terms to the left:

(2x-5)+(2x-5)+x+x-(38)=0

We add all the numbers together, and all the variables

2x+(2x-5)+(2x-5)-38=0

We get rid of parentheses

2x+2x+2x-5-5-38=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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