(2x-5)(x+3x-7=)

Solution for (2x-5)(x+3x-7=) equation:

(2x-5)(x+3x-7=)

We move all terms to the left:

(2x-5)(x+3x-7-())=0


We calculate terms in parentheses: +(2x-5)(x+3x-7-()), so:

2x-5)(x+3x-7-()

We add all the numbers together, and all the variables

5x-5)(x

Back to the equation:

+(5x-5)(x)


We multiply parentheses

5x^2-5x=0

a = 5; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·5·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*5}=\frac{10}{10}
=1
$