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(2x-5)(x+20)=90
We move all terms to the left:
(2x-5)(x+20)-(90)=0
We multiply parentheses ..
(+2x^2+40x-5x-100)-90=0
We get rid of parentheses
2x^2+40x-5x-100-90=0
We add all the numbers together, and all the variables
2x^2+35x-190=0
a = 2; b = 35; c = -190;
Δ = b2-4ac
Δ = 352-4·2·(-190)
Δ = 2745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2745}=\sqrt{9*305}=\sqrt{9}*\sqrt{305}=3\sqrt{305}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-3\sqrt{305}}{2*2}=\frac{-35-3\sqrt{305}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+3\sqrt{305}}{2*2}=\frac{-35+3\sqrt{305}}{4} $
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