(2x-5)(2x-3/2)=0

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Solution for (2x-5)(2x-3/2)=0 equation: 


x in (-oo:+oo)

(2*x-5)*(2*x-(3/2)) = 0

(2*x-5)*(2*x-3/2) = 0

( 2*x-3/2 )

2*x-3/2 = 0 // + 3/2

2*x = 3/2 // : 2

x = 3/2/2

x = 3/4

( 2*x-5 )

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

x in { 3/4, 5/2 }

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