(2x-45)=(4x-15)=(2x-45)

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Solution for (2x-45)=(4x-15)=(2x-45) equation: 



(2x-45)=(4x-15)=(2x-45)

We move all terms to the left:

(2x-45)-((4x-15))=0

We get rid of parentheses

2x-((4x-15))-45=0



We calculate terms in parentheses: -((4x-15)), so:

(4x-15)

We get rid of parentheses

4x-15

Back to the equation:

-(4x-15)



We get rid of parentheses

2x-4x+15-45=0

We add all the numbers together, and all the variables

-2x-30=0

We move all terms containing x to the left, all other terms to the right

-2x=30

x=30/-2

x=-15

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