(2x-4/x-1)=5

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Solution for (2x-4/x-1)=5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-(4/x)-1 = 5 // - 5

2*x-(4/x)-5-1 = 0

2*x-4*x^-1-5-1 = 0

2*x^1-4*x^-1-6*x^0 = 0

(2*x^2-6*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-6*x^1-4*x^0) = 0

x^1

2*x^2-6*x-4 = 0

2*x^2-6*x-4 = 0

DELTA = (-6)^2-(-4*2*4)

DELTA = 68

DELTA > 0

x = (68^(1/2)+6)/(2*2) or x = (6-68^(1/2))/(2*2)

x = (2*17^(1/2)+6)/4 or x = (6-2*17^(1/2))/4

x in { (6-2*17^(1/2))/4, (2*17^(1/2)+6)/4} 

x in { (6-2*17^(1/2))/4, (2*17^(1/2)+6)/4 }

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