(2x-4/2x+4)-(x-5/x+2)=3

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Solution for (2x-4/2x+4)-(x-5/x+2)=3 equation: 



(2x-4/2x+4)-(x-5/x+2)=3

We move all terms to the left:

(2x-4/2x+4)-(x-5/x+2)-(3)=0



Domain of the equation: 2x+4)!=0

x∈R





Domain of the equation: x+2)!=0

x∈R



We get rid of parentheses

2x-4/2x-x+5/x+4-2-3=0

We calculate fractions


2x-x+(-4x)/2x^2+10x/2x^2+4-2-3=0

We add all the numbers together, and all the variables

x+(-4x)/2x^2+10x/2x^2-1=0

We multiply all the terms by the denominator


x*2x^2+(-4x)+10x-1*2x^2=0

We add all the numbers together, and all the variables

10x+x*2x^2+(-4x)-1*2x^2=0

Wy multiply elements

2x^3-2x^2+10x+(-4x)=0

We get rid of parentheses

2x^3-2x^2+10x-4x=0

We do not support expression: x^3

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