(2x-4)/4=(4x+3)/3

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Solution for (2x-4)/4=(4x+3)/3 equation: 



(2x-4)/4=(4x+3)/3

We move all terms to the left:

(2x-4)/4-((4x+3)/3)=0

We calculate fractions


2x/()+(-((4x+3)*4)/()=0



We calculate terms in parentheses: +(-((4x+3)*4)/(), so:

-((4x+3)*4)/(

We multiply all the terms by the denominator


-((4x+3)*4)



We calculate terms in parentheses: -((4x+3)*4), so:

(4x+3)*4

We multiply parentheses

16x+12

Back to the equation:

-(16x+12)



We get rid of parentheses

-16x-12

Back to the equation:

+(-16x-12)



We get rid of parentheses

2x/()-16x-12=0

We multiply all the terms by the denominator


2x-16x*()-12*()=0

We add all the numbers together, and all the variables

2x-16x*()=0

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