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(2x-4)/3=(2x+16)/13
We move all terms to the left:
(2x-4)/3-((2x+16)/13)=0
We calculate fractions
2x/()+(-((2x+16)*3)/()=0
We calculate terms in parentheses: +(-((2x+16)*3)/(), so:We get rid of parentheses
-((2x+16)*3)/(
We multiply all the terms by the denominator
-((2x+16)*3)
We calculate terms in parentheses: -((2x+16)*3), so:We get rid of parentheses
(2x+16)*3
We multiply parentheses
6x+48
Back to the equation:
-(6x+48)
-6x-48
Back to the equation:
+(-6x-48)
2x/()-6x-48=0
We multiply all the terms by the denominator
2x-6x*()-48*()=0
We add all the numbers together, and all the variables
2x-6x*()=0
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