(2x-4)+(3x+2)=38

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Solution for (2x-4)+(3x+2)=38 equation: 



(2x-4)+(3x+2)=38

We move all terms to the left:

(2x-4)+(3x+2)-(38)=0

We get rid of parentheses

2x+3x-4+2-38=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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