(2x-4)(x-6)/3x+1=0

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Solution for (2x-4)(x-6)/3x+1=0 equation: 



(2x-4)(x-6)/3x+1=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We multiply parentheses ..

(+2x^2-12x-4x+24)/3x+1=0

We multiply all the terms by the denominator


(+2x^2-12x-4x+24)+1*3x=0

Wy multiply elements

(+2x^2-12x-4x+24)+3x=0

We get rid of parentheses

2x^2-12x-4x+3x+24=0

We add all the numbers together, and all the variables

2x^2-13x+24=0

a = 2; b = -13; c = +24;
Δ = b2-4ac
Δ = -132-4·2·24
Δ = -23
Delta is less than zero, so there is no solution for the equation

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