(2x-4)(3x+2)=(x-1)(6x+2)

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Solution for (2x-4)(3x+2)=(x-1)(6x+2) equation: 



(2x-4)(3x+2)=(x-1)(6x+2)

We move all terms to the left:

(2x-4)(3x+2)-((x-1)(6x+2))=0

We multiply parentheses ..

(+6x^2+4x-12x-8)-((x-1)(6x+2))=0



We calculate terms in parentheses: -((x-1)(6x+2)), so:

(x-1)(6x+2)

We multiply parentheses ..

(+6x^2+2x-6x-2)

We get rid of parentheses

6x^2+2x-6x-2

We add all the numbers together, and all the variables

6x^2-4x-2

Back to the equation:

-(6x^2-4x-2)



We get rid of parentheses

6x^2-6x^2+4x-12x+4x-8+2=0

We add all the numbers together, and all the variables

-4x-6=0

We move all terms containing x to the left, all other terms to the right

-4x=6

x=6/-4

x=-1+1/2

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