(2x-4)(-3-x)=28

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Solution for (2x-4)(-3-x)=28 equation: 



(2x-4)(-3-x)=28

We move all terms to the left:

(2x-4)(-3-x)-(28)=0

We add all the numbers together, and all the variables

(2x-4)(-1x-3)-28=0

We multiply parentheses ..

(-2x^2-6x+4x+12)-28=0

We get rid of parentheses

-2x^2-6x+4x+12-28=0

We add all the numbers together, and all the variables

-2x^2-2x-16=0

a = -2; b = -2; c = -16;
Δ = b2-4ac
Δ = -22-4·(-2)·(-16)
Δ = -124
Delta is less than zero, so there is no solution for the equation

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