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(2x-33)(4x-163)=180
We move all terms to the left:
(2x-33)(4x-163)-(180)=0
We multiply parentheses ..
(+8x^2-326x-132x+5379)-180=0
We get rid of parentheses
8x^2-326x-132x+5379-180=0
We add all the numbers together, and all the variables
8x^2-458x+5199=0
a = 8; b = -458; c = +5199;
Δ = b2-4ac
Δ = -4582-4·8·5199
Δ = 43396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{43396}=\sqrt{4*10849}=\sqrt{4}*\sqrt{10849}=2\sqrt{10849}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-458)-2\sqrt{10849}}{2*8}=\frac{458-2\sqrt{10849}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-458)+2\sqrt{10849}}{2*8}=\frac{458+2\sqrt{10849}}{16} $
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