(2x-30)-(3x-54)-(4x-72)+48=120

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Solution for (2x-30)-(3x-54)-(4x-72)+48=120 equation: 



(2x-30)-(3x-54)-(4x-72)+48=120

We move all terms to the left:

(2x-30)-(3x-54)-(4x-72)+48-(120)=0

We add all the numbers together, and all the variables

(2x-30)-(3x-54)-(4x-72)-72=0

We get rid of parentheses

2x-3x-4x-30+54+72-72=0

We add all the numbers together, and all the variables

-5x+24=0

We move all terms containing x to the left, all other terms to the right

-5x=-24

x=-24/-5

x=4+4/5

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