(2x-3)=(9x+12)

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Solution for (2x-3)=(9x+12) equation: 



(2x-3)=(9x+12)

We move all terms to the left:

(2x-3)-((9x+12))=0

We get rid of parentheses

2x-((9x+12))-3=0



We calculate terms in parentheses: -((9x+12)), so:

(9x+12)

We get rid of parentheses

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

2x-9x-12-3=0

We add all the numbers together, and all the variables

-7x-15=0

We move all terms containing x to the left, all other terms to the right

-7x=15

x=15/-7

x=-2+1/7

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