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(2x-3)/7=x+32
We move all terms to the left:
(2x-3)/7-(x+32)=0
We get rid of parentheses
(2x-3)/7-x-32=0
We multiply all the terms by the denominator
(2x-3)-x*7-32*7=0
We add all the numbers together, and all the variables
(2x-3)-x*7-224=0
Wy multiply elements
(2x-3)-7x-224=0
We get rid of parentheses
2x-7x-3-224=0
We add all the numbers together, and all the variables
-5x-227=0
We move all terms containing x to the left, all other terms to the right
-5x=227
x=227/-5
x=-45+2/5
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