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(2x-3)/6=2x=1/2
We move all terms to the left:
(2x-3)/6-(2x)=0
We add all the numbers together, and all the variables
-2x+(2x-3)/6=0
We multiply all the terms by the denominator
-2x*6+(2x-3)=0
Wy multiply elements
-12x+(2x-3)=0
We get rid of parentheses
-12x+2x-3=0
We add all the numbers together, and all the variables
-10x-3=0
We move all terms containing x to the left, all other terms to the right
-10x=3
x=3/-10
x=-3/10
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