(2x-3)/6=(x+9)/4

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Solution for (2x-3)/6=(x+9)/4 equation: 



(2x-3)/6=(x+9)/4

We move all terms to the left:

(2x-3)/6-((x+9)/4)=0

We calculate fractions


2x/()+(-((x+9)*6)/()=0



We calculate terms in parentheses: +(-((x+9)*6)/(), so:

-((x+9)*6)/(

We multiply all the terms by the denominator


-((x+9)*6)



We calculate terms in parentheses: -((x+9)*6), so:

(x+9)*6

We multiply parentheses

6x+54

Back to the equation:

-(6x+54)



We get rid of parentheses

-6x-54

Back to the equation:

+(-6x-54)



We get rid of parentheses

2x/()-6x-54=0

We multiply all the terms by the denominator


2x-6x*()-54*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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