(2x-3)/4+x=(2x+3)/2+7

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Solution for (2x-3)/4+x=(2x+3)/2+7 equation: 



(2x-3)/4+x=(2x+3)/2+7

We move all terms to the left:

(2x-3)/4+x-((2x+3)/2+7)=0

We add all the numbers together, and all the variables

x+(2x-3)/4-((2x+3)/2+7)=0

We calculate fractions


x+(4x-6)/()+(-((2x+3)*4)/()=0



We calculate terms in parentheses: +(-((2x+3)*4)/(), so:

-((2x+3)*4)/(

We multiply all the terms by the denominator


-((2x+3)*4)



We calculate terms in parentheses: -((2x+3)*4), so:

(2x+3)*4

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

-8x-12

Back to the equation:

+(-8x-12)



We get rid of parentheses

x+(4x-6)/()-8x-12=0

We multiply all the terms by the denominator


x*()+(4x-6)-8x*()-12*()=0

We add all the numbers together, and all the variables

x*()+(4x-6)-8x*()=0

We get rid of parentheses

x*()+4x-8x*()-6=0

We add all the numbers together, and all the variables

4x+x*()-8x*()-6=0

We move all terms containing x to the left, all other terms to the right

4x+x*()-8x*()=6

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