(2x-3)/3=(6x+2)/4

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Solution for (2x-3)/3=(6x+2)/4 equation: 



(2x-3)/3=(6x+2)/4

We move all terms to the left:

(2x-3)/3-((6x+2)/4)=0

We calculate fractions


2x/()+(-((6x+2)*3)/()=0



We calculate terms in parentheses: +(-((6x+2)*3)/(), so:

-((6x+2)*3)/(

We multiply all the terms by the denominator


-((6x+2)*3)



We calculate terms in parentheses: -((6x+2)*3), so:

(6x+2)*3

We multiply parentheses

18x+6

Back to the equation:

-(18x+6)



We get rid of parentheses

-18x-6

Back to the equation:

+(-18x-6)



We get rid of parentheses

2x/()-18x-6=0

We multiply all the terms by the denominator


2x-18x*()-6*()=0

We add all the numbers together, and all the variables

2x-18x*()=0

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