(2x-3)/3=(3x-2)/6

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Solution for (2x-3)/3=(3x-2)/6 equation: 



(2x-3)/3=(3x-2)/6

We move all terms to the left:

(2x-3)/3-((3x-2)/6)=0

We calculate fractions


2x/()+(-((3x-2)*3)/()=0



We calculate terms in parentheses: +(-((3x-2)*3)/(), so:

-((3x-2)*3)/(

We multiply all the terms by the denominator


-((3x-2)*3)



We calculate terms in parentheses: -((3x-2)*3), so:

(3x-2)*3

We multiply parentheses

9x-6

Back to the equation:

-(9x-6)



We get rid of parentheses

-9x+6

Back to the equation:

+(-9x+6)



We get rid of parentheses

2x/()-9x+6=0

We multiply all the terms by the denominator


2x-9x*()+6*()=0

We add all the numbers together, and all the variables

2x-9x*()=0

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