(2x-3)/3+(3x+1)/5=x+1

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Solution for (2x-3)/3+(3x+1)/5=x+1 equation: 


x in (-oo:+oo)

(2*x-3)/3+(3*x+1)/5 = x+1 // - x+1

(2*x-3)/3+(3*x+1)/5-x-1 = 0

(5*(2*x-3))/(3*5)+(3*(3*x+1))/(3*5)+(3*5*(-x))/(3*5)+(-1*3*5)/(3*5) = 0

5*(2*x-3)+3*(3*x+1)+3*5*(-x)-1*3*5 = 0

19*x-15*x-15-12 = 0

4*x-15-12 = 0

4*x-27 = 0

(4*x-27)/(3*5) = 0

(4*x-27)/(3*5) = 0 // * 3*5

4*x-27 = 0

4*x-27 = 0 // + 27

4*x = 27 // : 4

x = 27/4

x = 27/4

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