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(2x-3)/(x-5)=12/3
We move all terms to the left:
(2x-3)/(x-5)-(12/3)=0
Domain of the equation: (x-5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=5
x∈R
(2x-3)/(x-5)-4=0
We multiply all the terms by the denominator
(2x-3)-4*(x-5)=0
We multiply parentheses
(2x-3)-4x+20=0
We get rid of parentheses
2x-4x-3+20=0
We add all the numbers together, and all the variables
-2x+17=0
We move all terms containing x to the left, all other terms to the right
-2x=-17
x=-17/-2
x=8+1/2
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