(2x-3)+6=12x+39

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Solution for (2x-3)+6=12x+39 equation: 



(2x-3)+6=12x+39

We move all terms to the left:

(2x-3)+6-(12x+39)=0

We get rid of parentheses

2x-12x-3-39+6=0

We add all the numbers together, and all the variables

-10x-36=0

We move all terms containing x to the left, all other terms to the right

-10x=36

x=36/-10

x=-3+3/5

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