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(2x-3)+4=5x+2(3x+5)
We move all terms to the left:
(2x-3)+4-(5x+2(3x+5))=0
We get rid of parentheses
2x-(5x+2(3x+5))-3+4=0
We calculate terms in parentheses: -(5x+2(3x+5)), so:We add all the numbers together, and all the variables
5x+2(3x+5)
We multiply parentheses
5x+6x+10
We add all the numbers together, and all the variables
11x+10
Back to the equation:
-(11x+10)
2x-(11x+10)+1=0
We get rid of parentheses
2x-11x-10+1=0
We add all the numbers together, and all the variables
-9x-9=0
We move all terms containing x to the left, all other terms to the right
-9x=9
x=9/-9
x=-1
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