(2x-3)+(x+3)+x=36

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Solution for (2x-3)+(x+3)+x=36 equation: 



(2x-3)+(x+3)+x=36

We move all terms to the left:

(2x-3)+(x+3)+x-(36)=0

We add all the numbers together, and all the variables

x+(2x-3)+(x+3)-36=0

We get rid of parentheses

x+2x+x-3+3-36=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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