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(2x-3)(1/5-x)=0
Domain of the equation: 5-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)!=-5
x!=-5/1
x!=-5
x∈R
(2x-3)(-1x+1/5)=0
We multiply parentheses ..
(-2x^2+2x^2+3x-3*1/5)=0
We multiply all the terms by the denominator
(-2x^2+2x^2+3x-3*1=0
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