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(2x-3)(5x+1)=2x+2/5
We move all terms to the left:
(2x-3)(5x+1)-(2x+2/5)=0
We add all the numbers together, and all the variables
(2x-3)(5x+1)-(+2x+2/5)=0
We get rid of parentheses
(2x-3)(5x+1)-2x-2/5=0
We multiply parentheses ..
(+10x^2+2x-15x-3)-2x-2/5=0
We multiply all the terms by the denominator
((+10x^2+2x-15x-3))*5-2x*5-2=0
Wy multiply elements
((+10x^2+2x-15x-3))*5-10x-2=0
We move all terms containing x to the left, all other terms to the right
((+10x^2+2x-15x-3))*5-10x=2
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