(2x-3)(4x-4)=-7

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Solution for (2x-3)(4x-4)=-7 equation: 



(2x-3)(4x-4)=-7

We move all terms to the left:

(2x-3)(4x-4)-(-7)=0

We add all the numbers together, and all the variables

(2x-3)(4x-4)+7=0

We multiply parentheses ..

(+8x^2-8x-12x+12)+7=0

We get rid of parentheses

8x^2-8x-12x+12+7=0

We add all the numbers together, and all the variables

8x^2-20x+19=0

a = 8; b = -20; c = +19;
Δ = b2-4ac
Δ = -202-4·8·19
Δ = -208
Delta is less than zero, so there is no solution for the equation

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