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(2x-29)=(10x-27)
We move all terms to the left:
(2x-29)-((10x-27))=0
We get rid of parentheses
2x-((10x-27))-29=0
We calculate terms in parentheses: -((10x-27)), so:We get rid of parentheses
(10x-27)
We get rid of parentheses
10x-27
Back to the equation:
-(10x-27)
2x-10x+27-29=0
We add all the numbers together, and all the variables
-8x-2=0
We move all terms containing x to the left, all other terms to the right
-8x=2
x=2/-8
x=-1/4
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