(2x-20)+(3x+5)=180-(3x+5)

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Solution for (2x-20)+(3x+5)=180-(3x+5) equation: 



(2x-20)+(3x+5)=180-(3x+5)

We move all terms to the left:

(2x-20)+(3x+5)-(180-(3x+5))=0

We get rid of parentheses

2x+3x-(180-(3x+5))-20+5=0



We calculate terms in parentheses: -(180-(3x+5)), so:

180-(3x+5)

determiningTheFunctionDomain
-(3x+5)+180

We get rid of parentheses

-3x-5+180

We add all the numbers together, and all the variables

-3x+175

Back to the equation:

-(-3x+175)



We add all the numbers together, and all the variables

5x-(-3x+175)-15=0

We get rid of parentheses

5x+3x-175-15=0

We add all the numbers together, and all the variables

8x-190=0

We move all terms containing x to the left, all other terms to the right

8x=190

x=190/8

x=23+3/4

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