(2x-2)+(x+1)+x+(x+1)=5

Solution for (2x-2)+(x+1)+x+(x+1)=5 equation:

Simplifying
(2x + -2) + (x + 1) + x + (x + 1) = 5

Reorder the terms:
(-2 + 2x) + (x + 1) + x + (x + 1) = 5

Remove parenthesis around (-2 + 2x)
-2 + 2x + (x + 1) + x + (x + 1) = 5

Reorder the terms:
-2 + 2x + (1 + x) + x + (x + 1) = 5

Remove parenthesis around (1 + x)
-2 + 2x + 1 + x + x + (x + 1) = 5

Reorder the terms:
-2 + 2x + 1 + x + x + (1 + x) = 5

Remove parenthesis around (1 + x)
-2 + 2x + 1 + x + x + 1 + x = 5

Reorder the terms:
-2 + 1 + 1 + 2x + x + x + x = 5

Combine like terms: -2 + 1 = -1
-1 + 1 + 2x + x + x + x = 5

Combine like terms: -1 + 1 = 0
0 + 2x + x + x + x = 5
2x + x + x + x = 5

Combine like terms: 2x + x = 3x
3x + x + x = 5

Combine like terms: 3x + x = 4x
4x + x = 5

Combine like terms: 4x + x = 5x
5x = 5

Solving
5x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '5'.
x = 1

Simplifying
x = 1