(2x-2)+(2x+2)+(3x+1)=36

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Solution for (2x-2)+(2x+2)+(3x+1)=36 equation:


Simplifying
(2x + -2) + (2x + 2) + (3x + 1) = 36

Reorder the terms:
(-2 + 2x) + (2x + 2) + (3x + 1) = 36

Remove parenthesis around (-2 + 2x)
-2 + 2x + (2x + 2) + (3x + 1) = 36

Reorder the terms:
-2 + 2x + (2 + 2x) + (3x + 1) = 36

Remove parenthesis around (2 + 2x)
-2 + 2x + 2 + 2x + (3x + 1) = 36

Reorder the terms:
-2 + 2x + 2 + 2x + (1 + 3x) = 36

Remove parenthesis around (1 + 3x)
-2 + 2x + 2 + 2x + 1 + 3x = 36

Reorder the terms:
-2 + 2 + 1 + 2x + 2x + 3x = 36

Combine like terms: -2 + 2 = 0
0 + 1 + 2x + 2x + 3x = 36
1 + 2x + 2x + 3x = 36

Combine like terms: 2x + 2x = 4x
1 + 4x + 3x = 36

Combine like terms: 4x + 3x = 7x
1 + 7x = 36

Solving
1 + 7x = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 7x = 36 + -1

Combine like terms: 1 + -1 = 0
0 + 7x = 36 + -1
7x = 36 + -1

Combine like terms: 36 + -1 = 35
7x = 35

Divide each side by '7'.
x = 5

Simplifying
x = 5

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