(2x-2)(x+1)=17

Solution for (2x-2)(x+1)=17 equation:

Simplifying
(2x + -2)(x + 1) = 17

Reorder the terms:
(-2 + 2x)(x + 1) = 17

Reorder the terms:
(-2 + 2x)(1 + x) = 17

Multiply (-2 + 2x) * (1 + x)
(-2(1 + x) + 2x * (1 + x)) = 17
((1 * -2 + x * -2) + 2x * (1 + x)) = 17
((-2 + -2x) + 2x * (1 + x)) = 17
(-2 + -2x + (1 * 2x + x * 2x)) = 17
(-2 + -2x + (2x + 2x2)) = 17

Combine like terms: -2x + 2x = 0
(-2 + 0 + 2x2) = 17
(-2 + 2x2) = 17

Solving
-2 + 2x2 = 17

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2x2 = 17 + 2

Combine like terms: -2 + 2 = 0
0 + 2x2 = 17 + 2
2x2 = 17 + 2

Combine like terms: 17 + 2 = 19
2x2 = 19

Divide each side by '2'.
x2 = 9.5

Simplifying
x2 = 9.5

Take the square root of each side:
x = {-3.082207001, 3.082207001}