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(2x-19)(3x+x)=0
We add all the numbers together, and all the variables
(2x-19)(+4x)=0
We multiply parentheses ..
(+8x^2-76x)=0
We get rid of parentheses
8x^2-76x=0
a = 8; b = -76; c = 0;
Δ = b2-4ac
Δ = -762-4·8·0
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-76}{2*8}=\frac{0}{16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+76}{2*8}=\frac{152}{16} =9+1/2 $
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