(2x-17)/5=(17-2x)/10

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Solution for (2x-17)/5=(17-2x)/10 equation: 



(2x-17)/5=(17-2x)/10

We move all terms to the left:

(2x-17)/5-((17-2x)/10)=0

We add all the numbers together, and all the variables

(2x-17)/5-((-2x+17)/10)=0

We calculate fractions


2x/()+(-((-2x+17)*5)/()=0



We calculate terms in parentheses: +(-((-2x+17)*5)/(), so:

-((-2x+17)*5)/(

We multiply all the terms by the denominator


-((-2x+17)*5)



We calculate terms in parentheses: -((-2x+17)*5), so:

(-2x+17)*5

We multiply parentheses

-10x+85

Back to the equation:

-(-10x+85)



We get rid of parentheses

10x-85

Back to the equation:

+(10x-85)



We get rid of parentheses

2x/()+10x-85=0

We multiply all the terms by the denominator


2x+10x*()-85*()=0

We add all the numbers together, and all the variables

2x+10x*()=0

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